2x^2-10x=2x+18

Solution for 2x^2-10x=2x+18 equation:

2x^2-10x=2x+18

We move all terms to the left:

2x^2-10x-(2x+18)=0

We get rid of parentheses

2x^2-10x-2x-18=0

We add all the numbers together, and all the variables

2x^2-12x-18=0

a = 2; b = -12; c = -18;
Δ = b2-4ac
Δ = -122-4·2·(-18)
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{2}}{2*2}=\frac{12-12\sqrt{2}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{2}}{2*2}=\frac{12+12\sqrt{2}}{4}
$